back Solution to exercise 3.1.1 The implementation is straightforward : the difference of the area of a circle sector and a triangle. <sxh c> function A = csegarea(R, alpha) A = 1/2 * R^2 * alpha - 1/2*R^2*sin(alpha); endfunction </sxh> However less operations are done if we slightly rearange the terms: <sxh c> function A = csegarea(R, alpha) A = R^2 * (alpha - sin(alpha)) / 2; endfunction </sxh> en/teaching/subjects/it/labs/sol_3_1_1.txt Last modified: 2017/10/02 15:54(external edit)