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Solution to exercise 3.1.1

The implementation is straightforward : the difference of the area of a circle sector and a triangle. <sxh c>

  function A = csegarea(R, alpha)
     A = 1/2 * R^2 * alpha - 1/2*R^2*sin(alpha); 
  endfunction

</sxh>

However less operations are done if we slightly rearange the terms: <sxh c>

  function A = csegarea(R, alpha)
     A = R^2 * (alpha - sin(alpha)) / 2; 
  endfunction

</sxh>

  • en/teaching/subjects/it/labs/sol_3_1_1.txt
  • Last modified: 2017/10/02 15:54
  • (external edit)